mirror of
https://codeberg.org/forgejo/forgejo
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111 lines
3.1 KiB
Go
111 lines
3.1 KiB
Go
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// Copyright 2015, Joe Tsai. All rights reserved.
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// Use of this source code is governed by a BSD-style
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// license that can be found in the LICENSE.md file.
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package bzip2
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import "github.com/dsnet/compress/bzip2/internal/sais"
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// The Burrows-Wheeler Transform implementation used here is based on the
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// Suffix Array by Induced Sorting (SA-IS) methodology by Nong, Zhang, and Chan.
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// This implementation uses the sais algorithm originally written by Yuta Mori.
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//
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// The SA-IS algorithm runs in O(n) and outputs a Suffix Array. There is a
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// mathematical relationship between Suffix Arrays and the Burrows-Wheeler
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// Transform, such that a SA can be converted to a BWT in O(n) time.
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//
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// References:
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// http://www.hpl.hp.com/techreports/Compaq-DEC/SRC-RR-124.pdf
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// https://github.com/cscott/compressjs/blob/master/lib/BWT.js
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// https://www.quora.com/How-can-I-optimize-burrows-wheeler-transform-and-inverse-transform-to-work-in-O-n-time-O-n-space
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type burrowsWheelerTransform struct {
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buf []byte
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sa []int
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perm []uint32
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}
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func (bwt *burrowsWheelerTransform) Encode(buf []byte) (ptr int) {
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if len(buf) == 0 {
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return -1
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}
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// TODO(dsnet): Find a way to avoid the duplicate input string method.
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// We only need to do this because suffix arrays (by definition) only
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// operate non-wrapped suffixes of a string. On the other hand,
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// the BWT specifically used in bzip2 operate on a strings that wrap-around
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// when being sorted.
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// Step 1: Concatenate the input string to itself so that we can use the
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// suffix array algorithm for bzip2's variant of BWT.
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n := len(buf)
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bwt.buf = append(append(bwt.buf[:0], buf...), buf...)
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if cap(bwt.sa) < 2*n {
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bwt.sa = make([]int, 2*n)
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}
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t := bwt.buf[:2*n]
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sa := bwt.sa[:2*n]
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// Step 2: Compute the suffix array (SA). The input string, t, will not be
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// modified, while the results will be written to the output, sa.
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sais.ComputeSA(t, sa)
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// Step 3: Convert the SA to a BWT. Since ComputeSA does not mutate the
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// input, we have two copies of the input; in buf and buf2. Thus, we write
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// the transformation to buf, while using buf2.
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var j int
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buf2 := t[n:]
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for _, i := range sa {
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if i < n {
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if i == 0 {
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ptr = j
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i = n
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}
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buf[j] = buf2[i-1]
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j++
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}
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}
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return ptr
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}
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func (bwt *burrowsWheelerTransform) Decode(buf []byte, ptr int) {
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if len(buf) == 0 {
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return
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}
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// Step 1: Compute cumm, where cumm[ch] reports the total number of
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// characters that precede the character ch in the alphabet.
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var cumm [256]int
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for _, v := range buf {
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cumm[v]++
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}
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var sum int
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for i, v := range cumm {
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cumm[i] = sum
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sum += v
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}
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// Step 2: Compute perm, where perm[ptr] contains a pointer to the next
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// byte in buf and the next pointer in perm itself.
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if cap(bwt.perm) < len(buf) {
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bwt.perm = make([]uint32, len(buf))
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}
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perm := bwt.perm[:len(buf)]
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for i, b := range buf {
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perm[cumm[b]] = uint32(i)
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cumm[b]++
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}
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// Step 3: Follow each pointer in perm to the next byte, starting with the
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// origin pointer.
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if cap(bwt.buf) < len(buf) {
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bwt.buf = make([]byte, len(buf))
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}
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buf2 := bwt.buf[:len(buf)]
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i := perm[ptr]
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for j := range buf2 {
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buf2[j] = buf[i]
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i = perm[i]
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}
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copy(buf, buf2)
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}
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